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icang [17]
2 years ago
5

Graph represents the solution of 2y +6 > 4

Mathematics
1 answer:
NemiM [27]2 years ago
7 0

Answer:

y = -32

Step-by-step explanation:

brainliest?

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44 88 88 66 22 99 88 77 99 66 99 55 22 66 22 99 88 77 77 99 ​(a) minequals= 22 ​(simplify your​ answer.) upper q 1 equalsq1= not
d1i1m1o1n [39]

I’m sorry. What’s the question for this problem?

5 0
3 years ago
Please help me i need the answer
Amiraneli [1.4K]

Answer:

A

Step-by-step explanation:

7 0
2 years ago
I need 14 and 15 thanks
Bad White [126]
14)  The answer is a) y = 2x. 2 is the slope and the line does not cross over the Y axis in this picture so there is not a Y-intercept you can see.
15) You pretty much just estimate. On the graph when you find 50 minutes and go up its around 140. 50 x 2 is 100 minutes. so just multiply 140 by 2 and its 280 so just round to the closest one.
8 0
3 years ago
In a small town 68% of the people owned television 72% on radio and 12% owned neither television nor radio (1)represent the info
Naddika [18.5K]

Answer:

1.)

The Venn diagram is in the attachment

2).

percentage of the population that owns only television== 16%

Step-by-step explanation:

The Venn diagram Is represented in the attached photo.

Let's call The total people x

X = people that own only television+ people that own only radio+ people that own both television and radio+ people that own neither the two.

X= (0.68x -y) +(y) +(0.72x-y)+(0.12x)

X= 0.68x-y+y+0.72x-y+0.12x

X= 1.52x-y

Y= 1.52x-x

Y= 0.52x

People that own both= 52%

people that own only television

= (0.68x -y)

= 0.68x-0.52x

= 0.16x

percentage of the population that owns only television= 0.16*100

percentage of the population that owns only television= 16%

4 0
3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
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