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inysia [295]
3 years ago
14

You went out to lunch with three friends and your subtotal was $42 not including the sales tax of 6%.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

It's DEFINITELY 2.52

Step-by-step explanation:

Change 6% to a decimal, which will be .06! Times $42 Times.06 and you'll end with the answer $2.52 !!!

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X² - 40x-129 resolve into factor​
Lelu [443]

Answer:

(x - 43)(x + 3)

Step-by-step explanation:

consider the factors of the constant term (- 129) which sum to give the coefficient of the x- term (- 40)

the factors are - 43 and + 3 , since

- 43 × + 3 = - 129 and - 43 + 3 = - 40 , then

x² - 40x - 129 = (x - 43)(x + 3) ← in factored form

8 0
2 years ago
In a laboratory, under favorable conditions, a bacteria grows at an exponential rate. the number of cells C in the population is
Naily [24]
Selection C is appropriate.

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A. The population is constant at 8.

B. The population is constant at 24.

C. Matches the problem description.

D. The initial population is 24 and after 1 hour is 72.
4 0
3 years ago
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Help need to finish!!? 6 and 7
tatyana61 [14]
6. 3X6= 4xm
18=4m
Divide by 4
M=4.5

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3 0
3 years ago
3×-y=5,2×+y=5 pleaseplease ​
Tanya [424]

Answer:

x = 2

y = 1

Step-by-step explanation:

3x - y = 5..............(1)× 1

2x + y = 5...….......(2)× 1

3x - y = 5..............(3)

2x + y = 5.............(4)

Cancel y

3x + 2x = 5 + 5

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Divide both sides by 5

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Substitute for the value of y

3x - y = 5

3(2) - y = 5

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6 0
3 years ago
For the reaction 2Fe + O2 → 2FeO, how many grams of iron oxide are produced from 42.4 mol of iron?
Butoxors [25]

In the balanced reaction

2 Fe + O₂   →   2 FeO

2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.

Look up the molar mass of Fe and O:

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• O = 15.999 g/mol

Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is

(42.4 mol) × (71.835 g/mol) ≈ 3050 g

8 0
2 years ago
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