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3 years ago

The width of a rectangle is 11.4 meters and its length is 18.7Find the area.

Mathematics

1 answer:

vazorg [7]3 years ago

8 0

Answer:

Area = 213.18

Step-by-step explanation:

11.4 x 18.7 = 213.18

Hope this helps you! :)

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A ball is rolled at a velocity of 12m/sec.after 36 seconds,it comes to a stop what is the acceleration of the ball?

miv72 [106K]

acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Step-by-step explanation:

Initial Velocity = 12m/sec

time = 36 s

Final Velocity 0 m/sec (ball comes to stop)

Acceleration= ?

The formula used to find acceleration is:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

Putting values and finding acceleration:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

$Acceleration=\frac{0-12}{36}$

$Acceleration=\frac{-12}{36}$

$Acceleration=\frac{-1}{3}\,\,m/sec^2$

So, acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Keywords: Acceleration

Learn more about Acceleration at:

#learnwithBrainly

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3 years ago

Item 5<br> What is the interquartile range of this data set?

fomenos

Answer:

its 13.0

Step-by-step explanation:

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2 years ago

Working at home: According to the U.S Census Bureau, 41% of men who worked at home were college graduates. In a sample of 506 wo

sergejj [24]

Solution :

a). The point estimate of proportion of college graduates among women who work at home,

$\hat p =\frac{166}{506}$

= 0.3281

99.5% confidence interval

$=\left( \hat p \pm Z_{0.005/2} \sqrt{\frac{\hat p (1- \hat p)}{n}} \right)$

$=\left( 0.3281 \pm 2.81 \sqrt{\frac{0.3281 \times (1- 0.3281)}{506}} \right)$

$=(0.3281 \pm 0.0586)$

$=(0.2695, 0.3867)$

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3 years ago

Simplify to create an equivalent expression.

Murljashka [212]

Answer:

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Step-by-step explanation:

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2 years ago

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If f(x) = 3x2 - 2x+4 and g(x) = 5x + 6x - 8, find (f - g)(x)

Lorico [155]

Answer:

The answer is C.

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2 years ago

The width of a rectangle is 11.4 meters and its length is 18.7Find the area.​

The width of a rectangle is 11.4 meters and its length is 18.7Find the area.