Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = the average length of rods in a randomly selected bundle of steel rods
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= 0.65173
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
Answer: y=2x+4
Step-by-step explanation:
the line hits at 4 on the y axis and I did 2 rise, 1 run.
Answer:
A box = $11
Step-by-step explanation:
Given
Represent the first order with A and the second with B.
So, we have:
Solving (a): Find B.
To find B, we make use of:
Make B the subject
Substitute values for Total and A
Open bracket
Collect Like Terms
Solving (b): Cost of a box of light bulb
This means that:
Substitute 7x + 13 for Total
Collect Like Terms
Make x the subject
Answer:
-16/3 will be the answer for this question
