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alexandr1967 [171]
4 years ago
11

La somme de 3 nombre consécutifs est égale à 195. Quelle est le plus petit de ces trois nombres

Mathematics
1 answer:
Rasek [7]4 years ago
5 0
Soit (x-1) le premier nombre, le second sera x et le troisieme (x+1)
Donc (x-1) + x + (x+1) = 195
 3x = 195 et x = 195/3 = 65

Donc le premier chiffre est x- 1 = 65 -1 = 64 et la serie:
64, 65, 66
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(If A(2, -3), B(3,-2) and point C divides the line segment AB in the ratio of 1: 2, find OC.)​
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Answer:

A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)

Here c divide AB line in the ratio of 1:2

From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)

and y=(m1×y2+m2×y1)/(m1+m2)

where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;

so x=(3+4)/3

  or, x=7/3;

y=(-2-6)/3

 or, y=-8/3;

so, oc=√((0-7/3)²+(0-(-8/3))²)

oc=3.54

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A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4.
antiseptic1488 [7]

Answer:

<h2> 1.69</h2>

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

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