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Svetlanka [38]
2 years ago
12

The horizontal cross-sectional shapes of the prism given below are all congruent. A. True B. False

Mathematics
1 answer:
AlekseyPX2 years ago
7 0

Answer:

Option A. True

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shapes of the horizontal cross-sections of the cylinder in the figure are circles congruent with the circle at the base and at the top of the cylinder.

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Divide and simplify.
vredina [299]

Answer:

\frac{ {x}^{2} + 10x + 16 }{ {x }  {}^{2}  + 6x + 8} \div  \frac{1}{x + 2}

\frac{ {x}^{2} + 8 x+  2x + 16}{ {x}^{2}  + 4x + 2x + 8}  \times (x + 2)

\frac{x(x + 8) + 2 (x + 8)}{x(x + 4) + 2(x + 4)}  \times (x + 2)

\frac{( x + 8)(x + 2)}{(x + 2)(x + 4)}  \times ( x + 2)

\frac{( x + 8)(x + 2)}{(x + 4)}

3 0
2 years ago
A shopper bought shoes marked $40. the sales tax is 8%. how much did the shopper pay in all
guajiro [1.7K]
8% equals 3.2. If you add $40 plus $3.2 cents that shopper would of paid $43.2 cents.
6 0
3 years ago
Read 2 more answers
A probability experiment is conducted in which the sample space of the experiment is upper s equals { 1 comma 2 comma 3 comma 4
Softa [21]

You can think of this experiment as follows: you have to select a random number between 1 and 15, where each number is equally likely to appear.

Player A wins if 3,4,5 or 6 are picked.

Player B wind is 10,11 or 12 are picked.

Two events are said to be mutually​ exclusive if they cannot happen at the same time. So, in our metaphor, the question is: can we pick a particular number, so that both players win simultaneously?

The question is no, because if player A wins, we have picked 3,4,5 or 6, and player B wins with none of these numbers.

Similarly, if player B wins, we have picked 10, 11 or 12, and player A wins with none of these numbers.

So, the two events cannot occur simultaneously.

If you want to be more formal, since the events are subset of the sample space, two events are mutually exclusive if their intersection is the empty set, and this is the case:

A \cap B = \{3,4,5,6\}\cap\{10,11,12\} = \emptyset

8 0
3 years ago
I’m confused on this one
Elina [12.6K]
The question is asking for the sector arc length WZ,which can be find through the sector formula:
2\pi \: r \times  \frac{angle}{ {360}^{o} }
Since both cz and wz are the radius, they have the same length
cz=wz=5 in.

In this case,
2丌(5)× 122°/360°
=10丌×61/180
=61/36 ×丌
≈5.32in.

Thus 5.32in. is the answer.

Hope it helps!
8 0
2 years ago
Solve 2(4x + 5) > 7x + 20.
choli [55]
2(4x+5)>7x+20  perform indicated multiplication on left side

8x+10>7x+20  subtract 7x from both sides

x+10>20  subtract 10 from both sides

x>10

or in interval notation, x=(10, +oo)
8 0
3 years ago
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