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3 years ago

Kalo kita toxic di malam lailatul qadar itu toxicnya sama kaya 1000 bulan gak

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

8 0

I don’t know understand but yeah okay

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(4 x 10) + (2 x 104)<br> Give your answer in standard form

Goshia [24]

Answer: =248x

Step-by-step explanation: Hope this help :D

Let's simplify step-by-step.

4x(10)+2x(104)

=40x+208x

Combine Like Terms:

=40x+208x

=(40x+208x)

=248x

7 0

3 years ago

What is the value of 53 15 25 125 625 thank you

AfilCa [17]

The answer is 843... if you are talking about adding...

5 0

3 years ago

Read 2 more answers

Mutleys journey began on a boat, 2 feet above sea level. He dove down to twelve feet below sea level and then returned to the su

Lubov Fominskaja [6]

Answer:

Mutley would start at 2 feet above sea level or +2, he would then travel 12 feet below sea level (-12) to then return to the surface of the ocean (0). The integers from least to greatest: -12, 0, 2. Visual:

-12(dive level) * * * * * * * * * * * 0(sea level) * 2(boat)

Step-by-step explanation:

Using positive and negative integers, we can determine Mutleys journey above, below and at the surface of the ocean. The surface of the ocean represents his 'origin' or starting point, which is 0. The boat is above the surface or +2. When Mutley dives below the surface, he is at a negative level of the ocean. Think of it in terms of a number line - negative numbers are to the left of 0 and positive numbers are to the right of 0. The further we go to the left on the number line, the lower our number. In this case, -12 would be furthest to the left, then 0, followed by 2.

6 0

3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago

in the ambrose family the ages of the three children are three consecutive even integers . if the age of the youngest child is r

klemol [59]

The ages are consecutive even numbers.
The youngest child is (x+3) years old.
Every even number is 2 more than the one before it.
So the three ages are

   (x + 3), (x + 5), and (x + 7).

Their sum is x+3 + x+5 + x+7 = 3x + 15

But we're told that their sum is 42, so we can write

      3x + 15 = 42 <== the equation

Subtract 15 from each side: 3x   = 27

Divide each side by 3 : x   =   9 <== the solution

So the three ages are 12, 14, and 16.

The oldest child is 16 years old.

3 0

3 years ago