Hello!
a) 6 pounds
$9 is three times the cost we are given. Therefore, we multiply our original two pounds by three, giving us 6.
b) You would not be able to
There are 16 ounces in a pound. If each one weighs 5 ounces, it would be 5/16 of a pound. This would be 5/16 of $1.5, which is about 0.47. If we multiply this by 24 oranges, we get a cost 11.28, which is more than $9.
I hope this helps!
Answer:
The answer is below
Step-by-step explanation:
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x² + 16y² = 16
Solution:
Given that the ellipse has the equation: 4x² + 16y² = 16
let us make x the subject of the formula, hence:
4x² + 16y² = 16
4x² = 16 - 16y²
Dividing through by 4:
x² = (16 - 16y²)/4
x² = 4 - 4y²
Taking square root of both sides:
![x=\sqrt{4-4y^2 }\\](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B4-4y%5E2%20%7D%5C%5C)
The points of the rectangle vertices is at (x,y), (-x,y), (x,-y), (-x,-y). Hence the rectangle has length and width of 2x and 2y.
The area of a rectangle inscribed inside an ellipse is given by:
Area (A) = 4xy
A = 4xy
![A=4(\sqrt{4-4y^2} )y\\\\A=4y\sqrt{4-4y^2}=4\sqrt{4y^2-4y^4} \\\\The\ maximum\ area\ of\ the\ rectangle\ is\ at\ \frac{dA}{dy}=0\\\\ \frac{dA}{dy}=4(\frac{4-8y^2}{\sqrt{4-4y^2} } )\\\\4(\frac{4-8y^2}{\sqrt{4-4y^2} } )=0\\\\4-8y^2=0\\\\8y^2=4\\\\y^2=1/2\\\\y=\frac{1}{\sqrt{2} }\\\\x=\sqrt{4-4(\frac{1}{\sqrt{2} })^2}=\sqrt{2}](https://tex.z-dn.net/?f=A%3D4%28%5Csqrt%7B4-4y%5E2%7D%20%29y%5C%5C%5C%5CA%3D4y%5Csqrt%7B4-4y%5E2%7D%3D4%5Csqrt%7B4y%5E2-4y%5E4%7D%20%20%5C%5C%5C%5CThe%5C%20maximum%5C%20area%5C%20of%5C%20the%5C%20rectangle%5C%20is%5C%20at%5C%20%5Cfrac%7BdA%7D%7Bdy%7D%3D0%5C%5C%5C%5C%20%20%5Cfrac%7BdA%7D%7Bdy%7D%3D4%28%5Cfrac%7B4-8y%5E2%7D%7B%5Csqrt%7B4-4y%5E2%7D%20%7D%20%29%5C%5C%5C%5C4%28%5Cfrac%7B4-8y%5E2%7D%7B%5Csqrt%7B4-4y%5E2%7D%20%7D%20%29%3D0%5C%5C%5C%5C4-8y%5E2%3D0%5C%5C%5C%5C8y%5E2%3D4%5C%5C%5C%5Cy%5E2%3D1%2F2%5C%5C%5C%5Cy%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C%5C%5Cx%3D%5Csqrt%7B4-4%28%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%29%5E2%7D%3D%5Csqrt%7B2%7D)
Therefore the length = 2x = 2√2, the width = 2y = 2/√2
Area = length × width
Length = 1/2 yd
Area = 3/8 yd
All you have to do is divide area by length to get width
3/8 ÷ 1/2
Keep 3/8
Change ÷ to ×
Flip 1/2 to 2/1
That equals 3/8 × 2/1 = 6/8 = 3/4
Width = 3/4 yd
~Aamira~
Hope this helped☺☺
Answer:
The scale factor from figure A to figure B is 2.
Step-by-step explanation:
See the attached diagram.
In the diagram shown figure A and figure B are similar and the two quadrilateral have side lengths that are in the same proportion.
If we want to identify the ratio of side lengths of figure B to corresponding side lengths of figure A, then it is constant and
![\frac{44}{22} = \frac{20}{10} = \frac{64}{32} = \frac{80}{40} = 2](https://tex.z-dn.net/?f=%5Cfrac%7B44%7D%7B22%7D%20%3D%20%5Cfrac%7B20%7D%7B10%7D%20%3D%20%5Cfrac%7B64%7D%7B32%7D%20%3D%20%5Cfrac%7B80%7D%7B40%7D%20%3D%202)
Therefore, the scale factor from figure A to figure B is 2. (Answer)
Answer:
12+3lessthanequalto7
Step-by-step explanation:
12+3lessthanequalto7