A circle has diameter 9cm<br> a square has side length 5 cm

What’s the answer for this

Serhud [2]

Answer:

D

Step-by-step explanation:

4 0

3 years ago

Find the probability of being dealt a full house. (Round your answer to six decimal places.)?

vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

$\dbinom42\dbinom43=24$

and the number of ways of drawing 3 aces and 2 2s is the same,

$\dbinom43\dbinom42=24$

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

$2\dbinom{13}2\dbinom42\dbinom43=3744$

The total number of hands that can be drawn is

$\dbinom{52}5=2,598,960$

Then the probability of getting a full house is

$\dfrac{2\binom{13}2\binom42\binom43}{\binom{52}5}=\dfrac6{4165}\approx\boxed{0.001441}$

4 0

3 years ago

5x - 4 > 12<br> AND<br> 12x +5≤-4

LenaWriter [7]

Answer:

These two would not overlap each other when graphed so there is no solution.

6 0

3 years ago

When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?

Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

$a^{\frac{m}{n}}$ can be written as $\sqrt[n]{a^{m}}$
To simplify the radical factorize the base "a" to its prime factors

Example:

$(54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}}$ ,
Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = $2(3)^{3}$
$\sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}$
2² can not go out the radical because 2 is less than 3 not divisible by 3
$3^{6}$ can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
$\sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}$