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jasenka [17]
3 years ago
6

Ross and Annie do chores at their home acreage. Ross mows the acreage lawn every 12 days, and Annie bathes the dog every 21 days

. If Ross and Annie do their chores today, how many days will pass before they both do their chores again on the same day?
Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0
84 days will pay before they both do their chores again on the same day.
<span> <span> </span><span><span> Ross mows the lawn <span>      Annie bathes the dog </span>
</span> <span> 12 x 1 = 12                          21 x 1 =  21
</span> <span> 12 x 2 = 24                          21 x 2 =  42
</span> <span> 12 x 3 = 36                          21 x 3 =  63
</span> <span> 12 x 4 = 48                          21 x 4 =  84
</span> <span> 12 x 5 = 60                          21 x 5 = 105
</span> <span> 12 x 6 = 72                          21 x 6 = 126
</span> <span> 12 x 7 = 84                          21 x 7 = 147
</span> <span> 12 x 8 = 96                          21 x 8 = 168
</span> <span> 12 x 9  = 108                       21 x 9 = 189
</span> <span> 12 x 10 = 120                      21 x 10 = 210 </span></span></span>
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Answer:

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Which is the slope of the line that passes through the points (2, 8) and (4, 6)?​
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Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
3 years ago
is 20% in a decimal 0.20 in fraction 20/50 54% is a 40 0.4 fraction 4/10 decimal percent 9% decimal 0.9 fraction 9/10 66% 0.66 6
Gre4nikov [31]
20% is .20/ 20/50 is 40% or .4 or 4/10/ 9% is .09 or 9/100 / 9/10 is 90% or .9/ 66% is .66 or 33/50 or 66/100/ 6/10 is 60% or 60/100 or .6/ 2% is .02 or 1/50 or 2/100. I didn't exactly understand the question, but I hope this answers your question.
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3 years ago
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