A. 1/6, 6 possible outcomes with 1 desired result.
B.67/450 will give you the answer of 14.888...% I'm going to assume your teacher will let you round to 15 so the chances are 15/100 and in simplest form is 3/20.
Answer:
The fourth vertex is D(8, 0)
Step-by-step explanation:
Let A(0, 0), B(2, 4), and C(10, 4) be the three vertices of a parallelogram ABCD and let its fourth vertex be D(a, b).
Join AC and BD. Let AC and BD intersect at point O.
- We have known that the diagonals of a parallelogram bisect each other.
So, O would be the midpoint of AC as well as that of BD.


The midpoint of AC is:




The midpoint of BD is:

so
∵ 


∵ 


Hence, the fourth vertex is D(8, 0)
10x^6y^3 + 20x^3y^2 / 5x^3y =
5x^3y (2x^3y^2 + 4y) / 5x^3y=
<span>2x^3y^2 + 4y
</span>
First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1.
<span>Hope you understand!
</span>
I like to be ____ like a ____ 3+ 600 = 306:)