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lukranit [14]
3 years ago
7

A number cube is rolled 450 times. The number 3 comes up 67 times. A, what is the theoretical probability of rolling a 3? Write

your answer as a fraction in simplest form. B. What is the experimental probability of rolling 3? Write your answer as a fraction in simplest form.
Mathematics
2 answers:
Mila [183]3 years ago
6 0
A)  Thoeretical probability:

(number of specific outcomes)/(number of total possible outcomes)

P(3)=1/6

B)  Experimental probability:

(number of specific outcomes observed)/(total number of observations)

P(3)=67/450 
Margarita [4]3 years ago
5 0
A. 1/6, 6 possible outcomes with 1 desired result.
B.67/450 will give you the answer of 14.888...% I'm going to assume your teacher will let you round to 15 so the chances are 15/100 and in simplest form is 3/20.
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4.<br> -2(x+3y)= 18<br> Plz help me!!!
OLEGan [10]

Answer:

x+3y=-9

Step-by-step explanation:

-2(x+3y)=18

x+3y=18/-2

x+3y=-9

7 0
3 years ago
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densk [106]

See the attached picture.

8 0
2 years ago
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y&lt;35x−1.5 y&gt;35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
Solve 12x<br>x + 16 - 1 = 0<br>​
zhuklara [117]

Answer:

xx=-0.8

Step-by-step explanation:

not sure if this is right because the 12xx is kind of strange

12xx+16-1=0
12xx+15=0
12xx=-15
12/12xx=12/-15
xx=-.8

5 0
2 years ago
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