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Elena-2011 [213]
3 years ago
15

What is the solution to the linear system x=-6y+15 and -2y+5x =11

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
7 0

After solving the linear system, value of x=3 and value of y=2

Step-by-step explanation:

We need to find the solution to the linear system x=-6y+15\,\,and\,\, -2y+5x =11

x=-6y+15\,\,\,\,(1)\\-2y+5x =11\,\,\,\,(1)

Putting value of equation (1) x=-6y+15 in equation(2)

-2y+5x =11\\-2y+5(-6y+15)=11\\-2y-30y+75=11\\-32y=11-75\\-32y=-64\\y=\frac{-64}{-32}\\y=2

value of y=2

Now putting the value of y in equation (1)

x=-6y+15\\x=-6(2)+15\\x=-12+15\\x=3

value of x = 3

After solving the linear system, value of x=3 and value of y=2

Keywords: Linear system

Learn more about Linear system at:

  • brainly.com/question/6075514
  • brainly.com/question/7490805
  • brainly.com/question/13168205

#learnwithBrainly

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2 years ago
What's the next number in the series. 65536, 256, 16..?
Artemon [7]
Hi there!

Since
65536 =  {256}^{2}
and
256 =  {16}^{2}
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So, the answer is 4.

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5 0
3 years ago
Solve each compound inequality<br><br> 10m &gt; 84
Mazyrski [523]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's solve :

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6 0
2 years ago
The graph shows the feasible region for the system with constraints:
Dimas [21]

Answer:

The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

The minimum value of the objective function C is 125

Step-by-step explanation:

* Lets look to the graph to answer the question

- There are 3 inequalities

# y ≤ 15 represented by horizontal line (purple line) and cut the

  y-axis at point (0 , 15)

# x + y ≤ 25 represented by a line (green line) and intersected the

  x-axis at point (25 , 0) and the y- axis at point (0 , 25)

# x + 2y ≥ 30 represented by a line (blue line) and intersected the

  x-axis at point (30 , 0) and the y-axis at point (0 , 15)

- The three lines intersect each other in three points

# The blue and purple lines intersected in point (0 , 15)

# The green and the purple lines intersected in point (10 , 15)

# The green and the blue lines intersected in point (20 , 5)

- The three lines bounded the feasible region

∴ The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

- To find the minimum value of the objective function C = 4x + 9y,

  substitute the three vertices of the feasible region in C and chose

  the least answer

∵ C = 4x + 9y

- Use point (0 , 15)

∴ C = 4(0) + 9(15) = 0 + 135 = 135

- Use point (10 , 15)

∴ C = 4(10) + 9(15) = 40 + 135 = 175

- Use point (20 , 5)

∴ C = 4(40) + 9(5) = 80 + 45 = 125

- From all answers the least value is 125

∴ The minimum value of the objective function C is 125

6 0
3 years ago
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2 is the right answer
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