<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
<h2>which question dear..maybe you forgot to add the attachment...</h2>
Answer:
dkdkdkdjdjd
Step-by-step explanation:
Answer:
8 1/3 cubes
Step-by-step explanation:
Hi
You should put into them.I mean
1-This is 2 part.First, you should put f(-1) then you should put what you found.
Solve is:f(-1)=3(-1)-2(-1)^2 so -3-2=-5 then put in other one:if f(-5):-15-50=-65
Is it correct?
