Answer:
Ok
Step-by-step explanation:
Thanks that was inspiring
Answer:
y = 17(2)^x
Step-by-step explanation:
If the graph of y = ab^x goes through (0, 17), then
17 = ab*0, or a = 17
Then the function is y = ab^x with a = 17, or
y = 17*b^x and we must find b.
If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true: 1088 = 17*b^6
which reduces to 64 = b^6
Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2
Then the desired exponential function is
y = 17(2)^x
Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
9514 1404 393
Answer:
(b) 40°
Step-by-step explanation:
Angle x and the one marked 70° are alternate interior angles, so are congruent. The sum of the two base angles of the isosceles triangle is ...
x° +x° = 70° +70° = 140°
So, the remaining angle 1 in the triangle is ...
180° -140° = 40°
∠1 = 40°