36 in. 12 in 10 in. Х

A hose fills a hot tub at a rate of 2.58 gallons per minute. How many hours will it take to fill a 268-gallon hot tub?

kakasveta [241]

Answer:

1.73 hours

Step-by-step explanation:

This can be solved with proportions.

$\frac{2.58 gallons}{1 minute} = \frac{268 gallons}{x minutes} \\$

Cross multiply and you get:

$2.58x gallons * minutes = 268 gallons * minutes\\$

Divide by 2.58 gallons and you get:

$x minutes = \frac{268 gallons}{2.58 gallons} * minutes \\x minutes = 103.876 minutes\\x = 103.876 minutes\\$

And to find out the number of hours that is, divide by 60 and you get 1.73 hours.

4 0

4 years ago

HELPP DUE IN THE NEXT HOUR

Sunny_sXe [5.5K]

[ 1, 1, 2, 2 ] [ 48, 49, 50, 51] Not sure about three, bro.

4 0

3 years ago

Lake forest and mission viejo are 14 miles apart. on a map, the two cities are 2 inches apart. How many miles does 1 inch repres

lesantik [10]

If two city’s are 14 miles apart and on a map they are 2 inches away. All you have to do is divide 14 by 2. Your answer is 7 miles per inch.

7 0

3 years ago

The amount of time the husband and the wife spend on house work is measured for 15 women and their 15 husbands. For the wives th

dolphi86 [110]

Answer:

The value of the test statistic is z = -0.877.

Step-by-step explanation:

Testing the difference in mean time spent on housework between husbands and wives.

At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:

$H_0: \mu_H - \mu_W = 0$

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.

$H_1: \mu_H - \mu_W \neq 0$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.

This means that $X = 4.5 - 7 = -2.5, s = 2.85$

What is the value of the test statistic for testing the difference in mean time spent on housework between husbands and wives?

$z = \frac{X - \mu}{s}$

$z = \frac{-2.5 - 0}{2.85}$

$z = -0.877$

The value of the test statistic is z = -0.877.

4 0

3 years ago

Helppppppppppppp pls

blagie [28]

Answer:

$\frac{1}{3^{2}}$ .

Step-by-step explanation:

Given $\frac{3^{4}}{3^{6}}$ :

Use the Quotient Rule for Exponents:

$\frac{a^{m} }{a^{n}} = a^{m-n}$

$\frac{3^{4}}{3^{6}} = 3^{4 - 6} = 3^{-2}$

Since it is a negative exponent, then you can use the Negative Exponent rule:

$a^{-n} = \frac{1}{a^{n}}$

$3^{-2} = \frac{1}{3^{2}}$

Therefore, the correct answer is $\frac{1}{3^{2}}$ .

8 0

3 years ago