2 years ago

Please give a real answer. What is the surface area of this composite figure?

Mathematics

1 answer:

dusya [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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In AEFG, F = 61 inches, ZF=79º and ZG=34°. Find the length of g, to the nearest<br> 10th of an inch.

DENIUS [597]

Answer:

g ≈ 34.7 in

Step-by-step explanation:

The law of sines is useful for this:

f/sin(F) = g/sin(G)

Multiplying by sin(G), we have ...

g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)

g ≈ 34.7 in

7 0

2 years ago

Opls help me fasttt plasee

Mademuasel [1]

soln,

here area of base = 25/4 unit ^ 2

height of the prism = 8/5 unit

so,

volume of prism = area of base x height of the prism

$= \frac{25}{4} \times \frac{8}{5}$

$= 10 \: \: {unit}^{2}$

so the volume of the prism is 10 unit^2

3 0

3 years ago

You have quarters and dimes that total $2.80. your friends says its possible that the number of quarters is 8 more than the numb

Sidana [21]

$\text{Let the number of dimes be x, then as per the friend the number of }\\
\text{quarters should be 8 more than dimes, so number of quarters}=x+8\\
\\
\text{we know that the value of 1 dime is }\$ 0.10 \text{ value of one quarter is }\$0.25\\
\\
\text{And since the total value of quarters and dimes is }\$2.80, \text{ so we have}\\
\\
0.10(x)+0.25(x+8)=2.80\\
\\
\Rightarrow 0.10x+0.25x+2=2.80\\
\\
\Rightarrow 0.35x=2.80-2\\
\\
\Rightarrow 0.35x=0.80$

$\Rightarrow x=\frac{0.80}{0.35}=2.29\\
\\
\text{so if we take 2 dimes then we'll have to take 10 quarters according to friend.}\\
\\
\text{So the statement of friend is }$ WRONG