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1 year ago

How many three-digit multiples of 5 have three different digits?

Mathematics

1 answer:

aalyn [17]1 year ago

8 0

There are 180 numbers which are three-digit multiples of 5.

According to the statement

we have to find the three digit numbers which are multiples of 5.

we know that three digit numbers are start from 100 to 999 and in 1 line of counting means 100 to 110 there are 2 numbers are multiples of 5.

Here we use Multiplication method to find the number of digit which are a multiple of 5.

It means there are two numbers which are multiples of 5 in the one line of counting and there are 90 lines of counting from 100 to 999.

So, it means the answer will become

2*90 = 180.

So, There are 180 numbers which are three-digit multiples of 5.

Learn more about NUMBERS here brainly.com/question/1094036

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Mumz [18]

Step-by-step explanation:

Part A: Linear Equation.

One of the points is (0,15). This means 0,15 is the y intercept so b=15.

We can find the slope

$\frac{5 - 15}{1 - 0 } = \frac{ - 10}{1} = - 10$

So our equation is

$y = - 10x + 15$

Part B: Exponential Equation

We know that

$15 = a \times b {}^{0}$

B to the zero power is 1 so

$15 = a$

This means a =15. Now let find b.

$5 = 15 \times b {}^{1}$

$\frac{1}{3} = b$

So the equation is

$y = 15( \frac{1}{3} ) {}^{x}$

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2 years ago

Chang is estimating the volume of his bathtub the actual volume of his bathtub is 37 gal chang’s estimate is 31 gal find the abs

stepladder [879]

<h3>The absolute error is 6</h3><h3>The percent error is 16.22 %</h3>

<em><u>Solution:</u></em>

Given that,

Actual volume of his bathtub is 37 gal

Estimate is 31 gal

<em><u>Find the absolute error</u></em>

Absolute Error = | Measured Value - Actual Value |

Absolute Error = | 31 - 37 |

Absolute Error = 6

<em><u>Find the percent error</u></em>

$Percent\ error = \frac{\text{estimate - actual}}{actual} \times 100$

Substituting we get,

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Negative sign means percent decrease

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2 years ago

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vfiekz [6]

Answer:

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Step-by-step explanation:

The discriminate is the portion of the quadratic equation under the square root

D = b^2 - 4ac

D = 8^2 - 4(2)(16)

D = 64 - 128

D = -64

Since the discriminate is negative the square root will be imaginary

and there will be 2 of them

2 imaginary roots

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Answer:

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