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mixer [17]
3 years ago
13

Find the difference between 9,000 and 8,745.

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer: 255

Step-by-step explanation: All you do is subtract 8,745 from 9000.

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Write down the value of the 7 in the number 5709.​
Dovator [93]

Answer:

700

Step-by-step explanation:

The 9 = 9

The 0 = 0

The 7 = 700

The 5 = 5000

8 0
3 years ago
Find g(x), where g(x) is the translation 7 units up of f(x)=x2.
AfilCa [17]

Answer:

g(x)=x^2+7

g(x) in the form a(x-h)^2+k would be:

g(x)=(x-0)^2+7

Step-by-step explanation:

Given:

Parent function:

f(x)=x^2

Translation occurs 7 units up to get g(x)

Translation Rules:

f(x)\rightarrow f(x)+c

If c>0 the function shifts c units to the up.

If c the function shifts c units to the down.

So, from the above rules g(x) can be represented as:

g(x)=f(x)+7     [7 units up]

g(x)=x^2+7

Writing g(x) in the form a(x-h)^2+k where a, h, and\ k are integers.

g(x)=1(x-0)^2+7

g(x)=(x-0)^2+7

3 0
3 years ago
Read 2 more answers
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
The number of tourists at the beach per weekend in July was 55,000, In November, the number of tourists per weekend was 18,000.
Ganezh [65]

Answer:

The percentage change from July to November is 67.27 %

Step-by-step explanation:

Given as :

The number of tourists at the beach per weekend in the month of July = x_1 = 55,000

The number of tourists at the beach per weekend in the month of November = x_2 = 18,000

Let the percentage change from July to November = A %

Or,  % decrease change = \dfrac{\tetxtrm new value - \textrm old value}{\textrm old value} × 100

So , A % = \dfrac{\tetxtrm [tex]x_2   - \textrm  x_1 }{\textrm  x_1 }[/tex] × 100

or, A % = \frac{55000 - 18000}{55000} × 100

Or, A % = \frac{37000}{55000} × 100

Or, A  = 67.27 %

So percentage change between two months = 67.27 %

Hence The percentage change from July to November is 67.27 % Answer

6 0
3 years ago
What is 500 times H88
sattari [20]
The answer would be A. 344000 and H=6 :)
8 0
3 years ago
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