Let's assume we were given 2 numbers: 15 and 30. Their sum is:

We want to express it as the product of GCF and another sum.
15 is divisible by: 1, 3, 5, 15
30 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30
The greatest number that appears in 2 series is 15.


In this case sum of two numbers can always be written as:
The bottom one is the correct answer.
Answer:
x = 3
Step-by-step explanation:
using the mid segment formula since quadrilateral WZYP is similar to that of MZYT, this is expressed as;
29 = 1/2(23 +11x+2)
Cross multiply
2(29) = 23+11x+2
58 = 25 + 11x
11x = 58 - 25
11x = 33
Divide both sides by 11
11x/11 = 33/11
x = 3
Hence the value of x is 3
3x3x3x3 = 81
x.x.x.x = x^4
2x2x2x2 = 16
B. 81x^4/16