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3 years ago

11

Write a corresponding real-world problem to represent 2x-125=400

1 answer:

MrRissso [65]3 years ago

7 0

2 x - 125 = 400

2 x = 400 + 125

2 x = 525

x = 525 / 2

<span>x = 262.5</span>

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Megan hughes deposits $4300 in an account that pays simple interest. when she withdraws her money 7 months later, she receives

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3 years ago

Given a geometric sequence in the table below, create the explicit formula and list any restrictions to the domain.

Makovka662 [10]

Given:

The geometric sequence is:

$n$ $a_n$

1 -4

2 20

3 -100

To find:

The explicit formula and list any restrictions to the domain.

Solution:

The explicit formula of a geometric sequence is:

$a_n=ar^{n-1}$ ...(i)

Where, a is the first term, r is the common ratio and $n\geq 1$ .

In the given sequence the first term is -4 and the second term is 20, so the common ratio is:

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Putting $a=-4,r=-5$ in (i), we get

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Therefore, the correct option is B.

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3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

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$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

3 years ago

Please help me with this.

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If you use a textbook for this i would recommend slader, it really works!!

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