Answer:
Yes Kevin is correct
Step-by-step explanation:
The index, x, of a radical ˣ√ is the numerical value of the root sought of the number located under (within) the radical sign
Therefore, when the index is even, we have, numbers for the radical given by 2x, therefore we have;
⁽²ˣ⁾√(a²ˣ)
Where a = The 2x root of the radicand
Therefore, we can write, a²ˣ = aˣ × aˣ
For which aˣ can be neqative but will still give a positive value
Therefore, when the index is even, the roots can either be a positive or a negative real number, which are two real numbers, +a or -a