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3 years ago

Will give brainliest.

Mathematics

2 answers:

slamgirl [31]3 years ago

7 0

Answer: standard form is

Ax + Bx= C

So the answer is

3x+8y=55

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Step-by-step explanation:

frez [133]3 years ago

3 0

Answer:

Ax + Bx= C

So ur answer will be

3x+8y=55

Step-by-step explanation:

I did this assignment and made a 100

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PLEASE HELP IM STUCK WITH THIS ONE AND I DONT KNOW :(

labwork [276]

The line crossing the two parallel lines forms an allied angle
So using the theory “allied angles add up to 180 degrees” we can find x

76 + x =180
x= 180-76
x=104 (Option B)

6 0

3 years ago

Factor 6y + 8y 6y² +8y?

german

Answer:uiuyiuytghjv 312

7iuty

Step-by-step explanation:

3 0

3 years ago

What is the factored form of the expression 144x2 - 49?

PIT_PIT [208]

Answer:

Step-by-step explanation:

Difference of squares: (a^2 - b^2) = (a - b)(a + b)

(144x^2 - 49) = (12x - 7) (12x + 7)

6 0

3 years ago

Read 2 more answers

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago

Determine the total cost or selling price to the nearest cent $65 video game ; 25% discount?

kodGreya [7K]

Answer:

48.75$

Step-by-step explanation:

the difference is about 16.25$

6 0

3 years ago