It always equal 0
hope this helps :)
In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
334.4 m²
Step-by-step explanation:
The formula for the area of a sector is given as:
1/2 × r² × θ
Where θ = Central angle
Area of a Circle = 700 m²
The formula for the area of a circle = πr²
r = Radius of a circle
r² = Area / π
r = √Area / π
r = √700/π
r = 14.927053304 m
Approximately, r = 14.93 m
Therefore, the area of the sector
= 1/2 × r² × θ
= 1/2 × 14.93² × 3 rad
= 334.35735 m²
Approximately, Area of the sector = 334.4 m²
I believe it is H I hope this helps !!!!
Answer:
9.78778777 is an irrational number.
