Question

Ayo show correct steps and get the right answer you'll get branliest its only one problem btw

Answer 1

Answer:

Solve

1

Distribute

3

+

6

(

−

2

)

=

6

0

3y+{\color{#c92786}{6(y-2)}}=60

3y+6(y−2)=60

3

+

6

−

1

2

=

6

0

3y+{\color{#c92786}{6y-12}}=60

3y+6y−12=60

2

Combine like terms

3

+

6

−

1

2

=

6

0

{\color{#c92786}{3y}}+{\color{#c92786}{6y}}-12=60

3y+6y−12=60

9

−

1

2

=

6

0

{\color{#c92786}{9y}}-12=60

9y−12=60

3

Add

1

2

12

12

to both sides of the equation

9

−

1

2

=

6

0

9y-12=60

9y−12=60

9

−

1

2

+

1

2

=

6

0

+

1

2

9y-12+{\color{#c92786}{12}}=60+{\color{#c92786}{12}}

9y−12+12=60+12

4

Simplify

Add the numbers

Add the numbers

again

9

=

7

2

9y=72

9y=72

5

Divide both sides of the equation by the same term

9

=

7

2

9y=72

9y=72

9

9

=

7

2

9

\frac{9y}{{\color{#c92786}{9}}}=\frac{72}{{\color{#c92786}{9}}}

99y​=972​

6

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

8

y=8

y=8

Solution

=

8

Step-by-step explanation:

y=8