Answer:
Yes.
Step-by-step explanation:
Option B was correct because it said that x was less than 1 so one couldn't be an answer. Knowing that you would have to pick one with an open circle showing that 1 couldn't be it so that narrows down the options to b or c. The line goes in the direction of the less than arrow (<) so that would point to answer b.
LnA +LnB= LnA.B
so we get <span>Log3(X-5)+log3(x+3)=Ln3(x-5)(x+3)=2 implies
</span>(x-5)(x+3)=2^3=8, so we can solve easily the quadratic equation
x^2-2x-23=0, there are two solution x=1 -sqrt(24), and x=1+sqrt(24)
Answer:
Step-by-step explanation:
The question to be solved is the following :
Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if 
. Recall that given two vectors a,b a⊥ b if and only if 
where 
is the dot product defined in 
. Suposse that 
. We want to find γ such that 
. Given that the dot product can be distributed and that it is linear, the following equation is obtained
Recall that 
are both real numbers, so by solving the value of γ, we get that
By construction, this γ is unique if 
, since if there was a 
such that 
, then
(12 times/16 seconds) = (x times/60 seconds)
x times = (12 times/16 seconds)*(60 seconds)
<span>x = 45 times</span>
