Answer:
(5x² + 3) (2x-3)
Step-by-step explanation:
10x³ - 15x² + 6x - 9 (rearrange)
10x³+ 6x - 15x² - 9 (group using parentheses)
(10x³+ 6x) - (15x² + 9) (factor out 2x from first term and 3 from second term)
2x (5x²+ 3) - 3(5x² + 3) (factor out (5x²+3) )
(5x² + 3) (2x-3) (answer)
Answer: The two roots are x = 3/2 and x = -2
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Explanation:
You have the right idea so far. But the two numbers should be 3 and -4 since
The -1 being the coefficient of the x term.
This means you need to change the -3x and 4x to 3x and -4x respectively. The other inner boxes are correct.
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Refer to the diagram below to see one way to fill out the box method, and that helps determine the factorization.
If we place a 2x to the left of -2x^2, then we need an -x up top because 2x*(-x) = -2x^2
Then based on that outer 2x, we need a -2 up top over the -4x. That way we get 2x*(-2) = -4x
So we have the factor -x-2 along the top
The last thing missing is the -3 to the left of 3x. Note how -3*(-x) = 3x in the left corner and -3*(-2) = 6 in the lower right corner.
We have the factor 2x-3 along the left side.
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The two factors are (2x-3) and (-x-2) which leads to the factorization (x+3)(-x+2)
The last thing to do is set each factor equal to 0 and solve for x
- 2x-3 = 0 solves to x = 3/2 = 1.5
- -x-2 = 0 solves to x = -2
The two roots are x = 3/2 and x = -2
Answer:
14 and 21 is the answer
Step-by-step explanation:
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Answer: Option A and Option C.
Step-by-step explanation:
For this exercise it is important to know the definition of "Vertical Angles".
When two lines intersect or cross, there are a pair of angles that share the same vertex and they are opposite each other. This pair of angles are known as "Vertical angles".
By definition, Vertical angles are congruent, which means that the have the equal measure.
In this case, you can observe in the picture provided in the exercise that the line TI and the line WN intersect each other at the point S.
You can identify that the pair of angles that are opposite to each other and share the same vertex are the shown below:
and 
and 