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3 years ago

If f(x)=x^2-11, for what values of z is f(x) < 25?

Mathematics

1 answer:

GuDViN [60]3 years ago

5 0

Answer:

Step-by-step explanation:

f(x) < 25

x² - 11 < 25

x² < 36

-6 < x < 6

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The points L(10,9) M(10,-5) N(-1,-5) and O(-1,9) form rectangle L M N O Which point is halfway between O and N.

tensa zangetsu [6.8K]

Answer:

C.) (-1, 2)

Step-by-step explanation:

You can plot the points on a graph, or you can just find the midpoint:

midpoint = (O + N)/2 = ((-1, 9) +(-1, -5))/2 = (-1-1, 9-5)/2 = (-2, 4)/2

midpoint = (-1, 2)

3 0

3 years ago

Which of these triangle pairs can be mapped to each other using a single translation?

sergeinik [125]

Answer:- D shows the triangle pairs which can be mapped to each other using a single translation.

Explanation:-

Translation is a rigid transformation which creates a congruent image as that of the original figure such that the distance between the each point of the original figure and the image is fixed and same.

The translation mapping is given by (x,y)→(x+h,y+k) ,where h is the distance of the x coordinate of the each point of the original figure to the image and k is the distance of the y coordinate of the each point of the original figure to the image.

In figure D we can see that the distance between each point of ΔCED is equal to the distance between each point of ΔMPN. Thus it shows the triangle pairs which can be mapped to each other using a single translation.

4 0

3 years ago

Read 2 more answers

A sequence has an initial value (I) of -17 and its fourth term (a4) is 35. What is its general equation? Its 14th term?

aleksley [76]

Answer:

The sequence is an Arthemtic Progression

An=A1+(n-1)d

A1 is first term, An is nth term, n is number of term, and d is common difference

therefore

A4=35, A1= -17

A4=A1+(4-1)d

35= -17+3d

35+17=3d

52=3d

52/3=3d/3

14=d

common diffrence(d)=14

The general solution is given by

An= -17+(n-1)14

An= -17+14n-14

An= -31+14n

An= 14n-31

A14 term, means n=14

From An=A1+(n-1)d

A14= -17+(14-1)14

= -17+(13×14)

= -17+182

= 165.

Therfore, the 14th term is 165.

2. A sequence has a CR of 4/5 and its eighth term (a8) is (393216/3125). What is its general equation? Its 3rd term?

solution

common ratio(r)=4/5

eighth term(G8)=393216/3125

From Gn= G1r^(n-1)

G8 means n=8

G8=G1r^(n-1)

393216/3125=G1(4/5)^(8-1)

393216/3125=G1(4/5)^7

G1=(393216/3125)/(4/5)^7

G1=600

The first term is given by G1=600

Therefore

The General equation is given by

The General equation is given by Gn= 600(4/5)^(n-1)

3rd term (G3)

G3= G1(4/5)^(3-1) where n=3,

=600(4/5)^2

=600(16/25)

=384

Therefore, the 3rd term is given by G3= 384.

I have made some Corrections i messed up somewhere.

7 0

3 years ago

3214325435435345353534

OLEGan [10]

Answer:

3214325435435345353534

Step-by-step explanation:

32143255345353534321432543543534535353432143254354353453535345345353534321432543543534535353432143254354353453535343214325534535353432143254354353453535343214325435435345353534534535353432143254354353453535343214325435435345353534

5 0

2 years ago

PLEASE HURRY WILL MARK ANSWER AS BRAINLIEST!!!

WITCHER [35]

Answer:

112

Step-by-step explanation:

5 0

3 years ago