Answer:
The total number of pencils is 6
Step-by-step explanation:
According to the given scenario, the computation of the total number of pencils is as follows:
There are 18 students
And let us assume there is m mechanical pencils that put in each bag
also he put twice of the regular pencil
So if he put the 3 mechanical pencil
So, the total number of pencils is
= 3 × 2
= 6
As it twice of the regular pencil
hence, the total number of pencils is 6
Answer:
x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically
x+y+2=-5 equation 1
-2x-y+2=-1 equation 2
x-2y-2=0 equation 3
Add equation 1 + 2+ 3
x+y+2=-5 + -2x-y+2+1 + x-2y-2
x+y+2= -7+2+1-2x+x+y
x+y+2= -4-x+y
x+y+2+4+x-y= 0
2x+6= 0
2x= -6
divide both side by 2
x= -3
from equation 1 insert x
x+y+2=-5
since x=-3
then, -3+2+y= -5
-1+y= -5
y= -5+1
y= -4
Step-by-step explanation:
Answer:
- 109°, obtuse
- 131°, obtuse
- 53°, acute
- 124°, obtuse
Step-by-step explanation:
You are exected to know the relationships of angles created where a transversal crosses parallel lines.
- Corresponding angles are equal (congruent).
- Adjacent angles are supplementary, as are any linear pair.
- Opposite interior (or exterior) angles are equal (congruent).
The appearance of the diagram often gives you a clue.
You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.
1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.
2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.
3. Opposite interior angles are equal, so w will be 53°. It is acute.
4. Corresponding angles are equal, so x will be 124°. It is obtuse.
