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FromTheMoon [43]
3 years ago
14

Find the distance between a and b

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:I believe it is 2.4

Step-by-step explanation:

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Suppose an experiment consists of randomly drawing a marble out of a bag and replacing the marble. the bag contains 3 yellow mar
Savatey [412]
Hi there!

Since the yellow marbles to the radio of total marbles is 3/15,

3/15 = 5

We need to divide the total amount is times the marble is drawn by the ratio.

20 ÷ 5 = 4

So, the yellow marble would be drawn 4 times.

Hope this helps!
4 0
3 years ago
Read 2 more answers
Solve the following equation <br><br>6x-1=3 (2x+4)-1
DIA [1.3K]
6x - 1 = 3(2x + 4) - 1
Distribute
6x - 1 = 6x + 12 - 1
Combine like terms
6x - 1 = 6x + 11
Add 1 and subtract 6x from each side
0 = 12
The equation has no real solution
4 0
3 years ago
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Find m∠4 if m∠1 = 100°
11111nata11111 [884]

Answer:

obtuse angle

Step-by-step explanation:

7 0
3 years ago
Eugene and three of his friends went out to eat. They decided to split the bill evenly. Each person paid $11. What was the total
Elena-2011 [213]

Answer:

Step-by-step explanation:

Je calcule la facture totale

11x4=44

La facture totale d'Eugène et ses trois amis était de 11$

8 0
1 year ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
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