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den301095 [7]
3 years ago
9

Can somebody help me??

Mathematics
1 answer:
xeze [42]3 years ago
4 0

Answer: two solutions and

Step-by-step explanation:

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Factoring trinomials<br> Select two for each
JulijaS [17]

Answer:

x² - 3x - 10 = (x - 5) (x + 2)

x² - 3x - 18 = (x + 3) (x - 6)

Step-by-step explanation:

<u>x² - 3x - 10</u>

x² + 2x - 5x - 10

x(x + 2) - 5(x + 2)

(x - 5) (x + 2)

<u>x² - 3x - 18</u>

x² - 6x + 3x - 18

x(x - 6) + 3(x - 6)

(x + 3) (x - 6)

<u>-TheUnknown</u><u>S</u><u>cientist</u>

4 0
3 years ago
Really stuck help <br> The picture below is the problem
iren [92.7K]

Answer:

Step-by-step explanation:

figure one

formula length x width x height

plug in 7 x 2 x 3

volume 42 cm^3

figure 2

formula length x width x height

plug in 3 x 2 x 7

volume 42 cm ^3

5 0
2 years ago
jane is twice as old as Barbara. Michael is 7 years older than Jane. If Michael is 21, which equation could be used to find Barb
dedylja [7]

Step-by-step explanation:

J = 2b

M = J + 7

M = 21

J = 21 - 7

J = 14

B = 7

<em>Equation:</em>

If M is J+7, so then J = 21-7. J is 2*b, so 2*b = 21-7. Then you subtract and divide.

3 0
3 years ago
The maths question for algebra is
ankoles [38]

Step-by-step explanation:

Let (2n +1) be the larger odd number by definition, where n can be any real integer. Then (2n - 1) is the smaller consecutive odd number.

The product of the 2 odd numbers is (2n + 1)(2n - 1) = 4n^2 - 1 = 2(2n^2) - 1. Since n^2 must be an integer, 2(2n^2) - 1 is odd. (Shown)

4 0
3 years ago
Identify the asymptotes of y=1 over x -6<br><br><br> A.<br> B.<br> C.<br> D.
Westkost [7]

Answer:

  D.  x = 0; y = -6

Step-by-step explanation:

There is a vertical asymptote at the value of x that makes the denominator zero. That value is x=0. This is sufficient to choose the correct answer.

When x gets large, the term 1/x nears zero, so the value of y nears -6. This is the horizontal asymptote.

  vertical asymptote: x = 0; horizontal asymptote: y = -6

6 0
3 years ago
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