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Yanka [14]
4 years ago
5

Leon bought a dozen daisies for $3.75. To the nearest hundredth, approximately how much did Leon pay for each daisy?

Mathematics
1 answer:
romanna [79]4 years ago
4 0

Answer: $0.31

Step-by-step explanation:

A dozen = 12

Cost of 12 daises = 3.75

Cost of one daisy = 3.75/12 = 0.3125

0.3125 to the nearest hundredth = 0.31  

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If 1 liter = 1.057 quarts, about how many liters are in 1 gallon of milk? Round to the nearest liter.
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The thrift store is selling their old DVDs. When the DVDs first came out, they sold for $19. They have now been marked down by 7
Luda [366]

Step-by-step explanation:

original price (100%) → $19

discounted price ((100-75)%) = (25%) → 25% x $19 = $4.75

8 0
3 years ago
Read 2 more answers
1. Use the interval 25% - 30% to find the monetary range that is recommended for the
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Answer:

(a) The monthly budget for housing would range from $2,291.50-$2,749.80.

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the good estimate would be $1,400.

Step-by-step explanation:

Explanation with steps are in the following attachment

5 0
3 years ago
Ok so I’m getting braces in a week and I’m pretty scared about it. But however, does it hurt when they put them in?
alina1380 [7]

Answer:

Ok so I've had braces and it doesn't really hurt getting put in but it does hurt when they tighten them but you have nothing to worry about :)

Step-by-step explanation:

3 0
4 years ago
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There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at a time, with replacement. Each time, the c
Firdavs [7]

I will use the binomial distrubion to find the probability.

\displaystyle
P(A)=\binom{n}{k}p^k(1-p)^{n-k}

------------------------------------------------------

A - selecting a red checker exactly 7 times in 10 selections

n=7\\
k=10

\displaystyle
P(A)=\binom{10}{7}\cdot\left(\dfrac{12}{15}\right)^7\cdot\left(1-\dfrac{12}{15}\right)^{10-7}\\\\
P(A)=\dfrac{10!}{7!3!}\cdot\left(\dfrac{4}{5}\right)^7\cdot\left(1-\dfrac{4}{5}\right)^3\\\\
P(A)=\dfrac{8\cdot9\cdot10}{2\cdot3}\cdot\dfrac{16384}{78125}\cdot\left(\dfrac{1}{5}\right)^3\\\\
P(A)=120\cdot\dfrac{16384}{78125}\cdot\dfrac{1}{125}\\\\
P(A)=\dfrac{393216}{1953125}\approx0.2=20\%


5 0
3 years ago
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