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3 years ago

Please Help!!!

Mathematics

2 answers:

Alenkinab [10]3 years ago

5 0

Answer:

The correct answer is A: 10

Step-by-step explanation:

We know that for Dance World the equation is y=15x and for Toe Tapper it is y=25+12.5x

Make a chart with both dance companies and compare the solutions to each equation. Like the one below.

Dance World / Toe Tappers

A:10 $150 / $150

B:15 $225 / $212.5

C:100 $1500 / $1275

D:150 $2250 / $1900

In conclusion, A:10 is the correct answer as both dance companies cost the same for 10 classes.

Sorry if this is really late, this is for the people who have the same question and need an answer too.

Zepler [3.9K]3 years ago

3 0

Answer:

The answer is that she would have to take D or 150 amount of classes

Step-by-step explanation:

Dance world = y = 15x

Toe tappers = y = 25 + 12.5x

See attached graph

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Mademuasel [1]

Answer:

m=21

Step-by-step explanation:

based on the dilation from 'ABC' to 'QRS' (which is 3) m should =21

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S_A_V [24]

#6 is 1.5 hours (Maria)

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3 years ago

a garden table and a bench cost $1,025 combined the garden table cost $75 more than the bench what is the cost of the bench

lukranit [14]

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3 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago

Find the y-intercept: 8x-3y=0

Alla [95]

Answer:

Step-by-step explanation:

The y-intercept is the value of y when x=0.

8(0) - 3y = 0

y = 0

y-intercept = 0

3 0

3 years ago