Set up a proportion
75/100= 9 baskets/ x attempts
The ratio of numerator to denominator should be 75/100 which simplifies to 3/4. 3/4= 9/x
3*3=9, 4*3=12
x=12
Final answer: 12 attempts
Yes. This equation given:
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" y = (½)x + 4 " ; in point-slope form; also known as: "slope-intercept form" ; is:
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" y = (½)x + 4 " .
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In other words, the equation given is ALREADY written in "point-slope form" ; or, "slope-intercept form".
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Note: An equation that is written in "point-slope form"
(or, "slope-intercept form"), is written in the format of:
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" y = mx + b " ;_________________
in which:_________________
"y" is a single, "stand-alone" variable on the "left-hand side of the equation"; "m" is the coefficient of "x"; also:
"m" is the slope of the line; which is what we want to solve for;
"b" is the "y-intercept"; or more precisely, the value of "x"
(that is; the "x-coordinate") of the point at which "y = 0";
that is, the value of "x" ; or the "x-coordinate" of the point at which
the graph of the equation crosses the "x-axis".
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Note that in our given equation, which is written in "point-slope form" (or, "slope-intercept form" — that is: " y = mx + b " ;
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which is: " y = (½)x + 4 " ;
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we have:
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"y" isolated as "stand-alone" variable on the "left-hand side" of the equation;
m = ½ ;
b = 4 .
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There are 55 hats at the beginning of the fire.
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values

Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC

-----> by SOH (opposite side divided by the hypotenuse)
substitute the values

therefore

Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC

-----> by TOA (opposite side divided by the adjacent side)
substitute the values

therefore

Domain: (-♾,2)U(2,♾), {x | x ≠2}
Range: (-♾,3) U(3,♾), {y | y ≠ 3}
Sorry that’s all I can help with