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Airida [17]
3 years ago
11

Suppose that every day from Monday through Friday,

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer: You take around 4,500 steps a day

Step-by-step explanation:

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Evaluate: tan(-120 degrees).
dem82 [27]
-120° = -2π/3 radians.

Tangent is defined as Opposite/Adjacent or Sine/Cosine in a unit circle. So, if you have memorized the unit circle,

sin(-2π/3) = √3/2
cos(-2π/3) = -1/2

So, tan(-2π/3) would be:
\frac{ \frac{ \sqrt{3} }{2} }{ \frac{-1}{2} } =  \frac{ \sqrt{3} }{2}* -\frac{2}{1}

Simplify, and you get:
-\frac{2 \sqrt{3} }{2}  = - \sqrt{3}

And, so, tan(-2π/3) = -√3
8 0
3 years ago
Can someone please help me
poizon [28]

Answer:

1) D

2) B

3) A

4) D

Step-by-step Explanation:

1) 1,300,000

= 1.3 × 10⁶

2) 0.052

= 5.2 × 10⁻²

3) 4,500

= 4.5 × 10³

4) 0.00061

= 6.1 × 10⁻⁴

3 0
4 years ago
Shelley’s pet food store sold one customer 5 peanut butter biscuits for $3. She sold another customer 7 beef treats for $4.20.
tatuchka [14]

Answer:

I think that is the answer to this math work 5 × 3= $15 7 × $4.20=$29.40 All together it will be $44.40

3 0
4 years ago
Read 2 more answers
Find the value of f(-3) for the function below. f(x) = 2x + 10
Allushta [10]

Answer:

4

Step-by-step explanation:

For this problem, we are trying find the output of when plug in -3 into 2x+10:

f(-3)=2(-3)+10=-6+10=4

4 0
3 years ago
The two box plots summarize the number of hours spent in the weight room for all the players on the football team
iragen [17]

Options:

A. Players at school 1 typically spent more time in the weight room than players at school 2.

B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8

School 2 has a median of 9.

As we can see, the median for school 1 is less than the median of school 2.

Interquartile range is the range of the box.

Interquartile range for school 1 = 10 - 4 = 6

Interquartile range for school 2 = 13 - 6 = 6

As we can also see, the interquartile range for school 1 and that of school 2 are equal.

7 0
4 years ago
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