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cupoosta [38]
3 years ago
5

Four children randomly line up, single file. What is the probability that they are in height order, with the shortest child in f

ront? All of the children are of different heights.
A 1/4
B 1/256
C 1/16
D 1/24
Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

the answer is D.  1/24

Step-by-step explanation:

The number of ways for the children to line up is 4!=4×3×2×1=24 -- there are 4 choices for who is first in line, then 3 for who is second, etc. Only one of these lines has the children in the order specified.

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Answer:

The simplified form is 5u^6x^2+\frac{4w x^{-3}}{3}

Step-by-step explanation:

To simplify the expression given to use, we need to reduce the given expression in its simplest form. There should not be any possibility for the further cancelling out of the division terms, if any.

Now the expression that is given to us is:

5u^6x^2+\frac{20wx}{15x^4}\\

Here we will simplify it, as follows:

5u^6x^2+\frac{20wx}{15x^4}\\=5u^6x^2+\frac{4w}{3x^3}\\=5u^6x^2+\frac{4w x^{-3}}{3}

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Answer:

Step-by-step explanation:

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