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Ratling [72]
3 years ago
8

Help What is the SSS postulate for triangle congruence?

Mathematics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

Side, Side, Side

Step-by-step explanation:

If 3 sides in one triangle are congruent to 3 sides in another triangle, then the triangles are congruent. This is called the Side-Side-Side (SSS) Postulate and it is a shortcut for proving that two triangles are congruent.

Hope this helps! <3

Olegator [25]3 years ago
5 0

<em>Answer:</em>

<em>If three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent. </em>

<em>Step-by-step explanation:</em>

<em>got it from gooogleeeeeeeee</em>

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Ronch [10]

Answer:

simply draw the same coordinates sideways at a 180 angle

Step-by-step explanation:


8 0
3 years ago
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
Find the slope intercept equation of the line perpendicular to the line 2X-5y=6 and containing the point (2,2)
Romashka [77]

Answer:

The equation of the perpendicular line would be y = -5/2x + 7

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

2x - 5y = 6

-5y = -2x + 6

y = 2/5x - 6/5

This shows us a slope of 2/5. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negate 2/5 to get -2/5 and then we flip it to get -5/2. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 2 = -5/2(x - 2)

y - 2 = -5/2x + 5

y = -5/2x + 7


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The answer is b, hope I helped :)
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None will be left b/c 54hrs is 19 more hrs than 35hrs. Half of the substance is already gone after only 35hrs
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3 years ago
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