Step-by-step explanation:
Cosecant is undefined at π/2, so we can rewrite this integral as:
lim(u→π/2) ∫ᵤᵖⁱ 35 csc(x) dx
lim(u→π/2) 35 ln│csc(x) − cot(x)│|ᵤᵖⁱ
lim(u→π/2) [35 ln│csc(π) − cot(π)│ − 35 ln│csc(u) − cot(u)│]
undefined
The integral diverges.
Answer:
200
Step-by-step explanation:
Out of those 6 numbers, 4 of them are prime sow we have the ratio of 2:3
2/3 * 300 = 200
1 pound is .45 kilograms
120 pounds is 54.4311 killograms
Hope that helps :)
Answer:
Step-by-step explanation:
Alright, lets get started.
Principal amount Joshua borrowed, P = $ 25000
rate of interest, r = 1.5 %
time, t = 2 years
simple interest =
simple interest =
Means $ 750 will be the interest of Joshua's loan.
So, Joshua needs to repay the SBA =
Hence, Joshua will repay $ 25750 to SBA after two years. : Answer
Hope it will help :)
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
<h3>What is the numerical value of DE?</h3>
Given the data in the question;
- E is a point between point D and F.
- Segment DF = 78
- Segment DE = 5x - 9
- Segment EF = 2x + 10
- Numerical value of DE = ?
Since E is a point between point D and F.
Segment DF = Segment DE + Segment EF
78 = 5x - 9 + 2x + 10
78 = 7x + 1
7x = 78 - 1
7x = 77
x = 77/7
x = 11
Hence,
Segment DE = 5x - 9
Segment DE = 5(11) - 9
Segment DE = 55 - 9
Segment DE = 46
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
Learn more about equations here: brainly.com/question/14686792
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