Consider the polynomials p left parenthesis x right parenthesis equals 21 x minus 4 x squared and q left parenthesis x right par
enthesis equals 5 . Find the x -coordinate(s) of the point(s) of intersection of these two polynomials. What is the sum of these x -coordinates
1 answer:
Answer:
21/4 = 5.25
Step-by-step explanation:
You want the sum of the x-values that are solutions to ...
21x -4x² = 5
4x² -21x +5 = 0 . . . . . subtract the left side, rearrange to standard form
x² -(21/4)x +5/4 = 0 . . . divide by 4
In this form the sum of the x-values that solve this equation is the opposite of the x-coefficient. That sum will be 21/4 = 5.25. (The attached graph confirms this result.)
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Consider a quadratic with roots p and q. It factors as ...
(x -p)(x -q) = 0 = x² -(p+q)x +pq
That is, the x-coefficient is the opposite of the sum of the roots p and q.
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Answer:
Step-by-step explanation:
(convert the mixed numbers into improper fractions = )
Steps if needed:
4*3 = 12+2 =14
6*10=60+7=67
=
Simplify: Divide by 2
|| 938/2 = 469 30/2 = 15
Convert your answer to a mixed fraction
469/15 = 31.26....
15*31 = 465
465+4 = 469
So your answer is 31 4/15
Answer:
Step-by-step explanation:
Given
See attachment
Required
Determine the slope of the line
From the attachment, we have the following points
and
The slope m is then calculated using:
Substitute values for the x's and y's
<em>Hence, the slope is 0</em>
Answer:
30
Step-by-step explanation:
Given: There are six finalists and two medals. That is it asks for the possibilities of 6 finalists taking two at a time. Say, for example the first and third finalist or the second and the sixth finalist and so on. The number of possibilities is given by
So the number of possibilities of 6 finalists taken two at a time is