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3 years ago

Multiplying - make sure your answer is in fraction form.

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Answer:

Multiplying - make sure your answer is in fraction form.

1.4 x 0.8 = 28/25

2.3 x 1.8 =207/50

2.37 x 1.2 =721/250

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NEED HELP ASAP PLEASE

IrinaVladis [17]

Z would also be 63 degrees. Triangle WXZ is isosceles, as sides WX and WZ are marked as congruent. This means that the two base angles of the triangle (the bottom two) are congruent. You already know that one of the base angles, X (or WXY), is 63 degrees, so using this reasoning, the other base angle, YZW, is 63 degrees as well. I hope this helps!

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4 years ago

Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k.

otez555 [7]

equation of f(x)

point of intersection of f(x) and x axis - (-4,0)

point of intersection of f(x) and y axis - (0,4)

Equation y = x +4

g(x) = f( kx)

= kx +4

g(-2) = -2

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3 years ago

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This figure is made up of a quadrilateral and a semicircle.

vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

$d =\sqrt({ x_{1}-x_{2})^2 +( y_{1} -y_{2} )^2}$

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = $\sqrt{(-1-(-2))^2+(2-(-1))^2}$

= $\sqrt{(-1+2)^2+(2+1)^2}$ (As negative times negative is positive)

= $\sqrt{(1)^2+(3)^2} =\sqrt{1+9} =\sqrt{10}$

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= $\sqrt(4-5)^2+(-3-0)^2}$

= $\sqrt{(-1)^2+(-3)^2}$

= $\sqrt{1+9} =\sqrt{10}$

So the sides AB and CD are equal.

The length of side AD

= $\sqrt{(-1-5)^2+(2-0)^2}$

= $\sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}$

The length of side BC

= $\sqrt{(-2-4)^2+(-1-(-3))^2}$

= $\sqrt{(-2-4)^2+(-1+3)^2}$

= $\sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}$

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is $\sqrt{40}$ and width is $\sqrt{10}$ .

Area of a rectangle = length × width

= $(\sqrt{40}) (\sqrt{10})$

= $\sqrt{(40)(10)}=\sqrt{400}$

= $20 unit^2$

Now the diameter of the semicircle is the side AD = $\sqrt{40}$

So, the radius of the semi-circle = $\frac{\sqrt{40}}{2}$

= $\frac{\sqrt{(4)(10)}}{2}$

= $\frac{(\sqrt{4})(\sqrt{10})}{2}$

= $\frac{2\sqrt{10}}{2}$ = $\sqrt{10}$

Area of semi-circle = $\frac{1}{2} \pi r^2$ , where r is the radius.

= $\frac{1}{2} \pi (\sqrt{10})^2$

= $\frac{1}{2} \pi (10)$

= $\frac{(\pi)(10)}{2}$

= $\frac{10\pi}{2} = 5\pi$ = $15.7 unit^2$ ( Approximately taken to the nearest tenth)

Total area of the figure = $(20+15.7) unit^2$ = $35.7 unit^2$

We have got the required answer.

Option a is correct here.

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3 years ago

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fiasKO [112]

Your question is incomplete but I'll just say how many gallons it would be for each mile.

Answer:

Step-by-step explanation:

500÷25=20

mark brainliest if helped :D

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3 years ago

The only way to circumscribe a circle around a parallelogram is to make the parallelogram a _____

belka [17]

The correct answer for the completion exercise shown above is: "Rectangle".
Then, the complete sentece is: <span>The only way to circumscribe a circle around a parallelogram is to make the parallelogram a rectangle.
The explanation is shown below:
By definition, a parallelogram is a four sided polygon (or a quadrilateral). Therefore, to circumsbribe a circle around this figure, all the vertexes must lie on the circle and it must have four angles of 90 degrees. So, it must be a rectangle. </span>

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3 years ago

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