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2 years ago

Write the equation for a line that passes through the origin and is parallel to x + y = 6

Mathematics

2 answers:

seraphim [82]2 years ago

8 0

Y=6-x I believe it would be I hope this helps

Studentka2010 [4]2 years ago

4 0

X=-y+6 and two points it passes on the graph are (0,6) and (6,0)

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The length of a rectangle is 1 units less than the width. The area of the rectangle is 20 units. What is the width, in units, of

Degger [83]

Answer:

Step-by-step explanation:

20 has many factors, including 4&5.

4 is one less than 5, so 4 is the length and 5 is our width.

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3 years ago

What is the slope-intercept equation for the line below? (0,2) (5,4)

Alla [95]

Find the slope first
m = (y₂ - y₁)/(x₂ - x₁)
m = (4-2)/(5-0)
m = 2/5

Find the slope-intercept equation
y - y₁ = m(x - x₁)
y - 2 = 2/5 (x - 0)
y - 2 = (2/5)x
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3 years ago

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What is the value of f(3) in the function below?

Pani-rosa [81]

Answer:

B.3/2

Step-by-step explanation:

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3 years ago

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Tadashi had a veggie pizza that was cut into 8 equal pieces. He ate 2 pieces and left the other 6 in the box. What fraction of t

Stella [2.4K]

Answer:

1/4

Step-by-step explanation:

2/8= 1/4

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2 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

2 years ago