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3 years ago

Can anyone answer this plz ill give brainliest

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

8 0

Answer: D. $1.00

Step-by-step explanation: Good luck! :D

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What Val are restricted from the domain of

djverab [1.8K]

Given:

The given expression is $\frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}$

We need to determine the values for which the domain is restricted.

Restricted values:

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

$(2x-1)^2\neq 0$

Taking square root on both sides, we get;

$2x-1\neq 0$

$2x\neq 1$

$x\neq \frac{1}{2}$

Thus, the restricted value from the domain is $x\neq \frac{1}{2}$

Hence, Option A is the correct answer.

7 0

4 years ago

Subtract -2x^2+4x-1 from 6x^2+3x-9 your answer should be a polynomial in standard form

Sphinxa [80]

the answer -8^2+1x-10

5 0

3 years ago

Read 2 more answers

Please solve these sums for 10 points

laila [671]

Answer:

(i) = 3

(ii) = 20

Step-by-step explanation:

x = 1

y = -2

z = -1

(i) 4x - 3y + 7z

4(1) - 3(-2) + 7(-1)

4 + 6 - 7 = 3

(ii) 2x³ - 6y²z + 3xyz²

2(1)³ - 6(-2)²(-1) + 3(1)(-2)(-1)²

2 + 24 - 6 = 20

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

Step-by-step explanation:

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

4 years ago

3x+y=9 and 3x=9-y solve each system by elimination to prove your answer, I am stuck on this one

Svetllana [295]

Infinitely many solutions.I will try to solve your system of equations.3x+y=9;3x=−y+9Step: Solve3x+y=9for y:3x+y+−3x=9+−3x(Add -3x to both sides)y=−3x+9Step: Substitute−3x+9foryin3x=−y+9:3x=−y+93x=−(−3x+9)+93x=3x(Simplify both sides of the equation)3x+−3x=3x+−3x(Add -3x to both sides)

so ur answer is
Infinitely many solutions.

7 0

3 years ago