Which formula gives the area of rectangle EFHG?

Mathematics

1 answer:

serg [7]3 years ago

6 0

The answer is area = (e + h) × j

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Pls help!!

Licemer1 [7]

Answer will be A, and if you need help with math work Connects is a great app to use

8 0

3 years ago

The set {3, 5, ?} could not be the sides of a triangle. 2 7 3 5

tresset_1 [31]

7 and 2 cannot be the lengths as on a triangle they're two equal side so two 3s or two 5s

6 0

3 years ago

Read 2 more answers

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

3 0

3 years ago

Hich is the joint relative frequency for the people who can only see the sunset?

UNO [17]

Answer:

12/38

Step-by-step explanation:

7 0

2 years ago

If the circumference of a circle measures 12π cm, what is the area of the circle in terms of π?

frez [133]

So the formula for the circumference of a circle is π x diameter
Since we know the the circumference already, we just divide that by π:

12π / π = 12

Now we halve the diameter to get the radius:
12 / 2 = 6

The area of a circle is π x radius²
So the area is:

·π x 6² = 36π· (or 113 not in terms of π)

5 0

3 years ago