Part A: Group A is a cluster of points. Group B Is not even a group this point is an outlier. A possible reason Point B is involved is because there could be a student that although played a lot of video games, he studied too and got a good score.
Part B: The association is a negative linear association. Also as students play more video games the test scores tend to go down.
Hope This Helps!
Answer:
MLH is congruent to JKI
LNK is congruent to HNI
I think that's how you're supposed to answer it...
The height of the tower roughly equals 41.421 meters.
The solution to the Questions are
- The alternate hypothesis demonstrates that there are two possible outcomes for the test.
- Decision rule: If z > 2.05 or z<-2.05, reject H0
- The two-tailed nature of the test is shown by the alternative hypothesis.
- The result of the test yields the following P-value: 0.0096
<h3>What is the alternate hypothesis?</h3>
(a)
The alternate hypothesis demonstrates that there are two possible outcomes for the test.
(b)
Here we have

(b)
Here the test is two-tailed. So for
, the critical values of the z-test are -2.05 and 2.05.
Decision rule: If z > 2.05 or z<-2.05, reject H0
(c)
Test statistics will be

z=2.59
(d)
The two-tailed nature of the test is shown by the alternative hypothesis.
(e)
The result of the test yields the following P-value: 0.0096
Read more about P-value
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The complete question in the attached figure
we know that
area each pasture=15000 ft²
area each pasture=x*y
so
15000=x*y-----> equation 1
perimeter two rectangular pastures=1050 ft
perimeter two rectangular pastures=2*[2x+y]+y----> 4x+2y+y---> 4x+3y
so
1050=4x+3y----> divide by 3----> 1050/3=(4/3)x+y
clear variable y
y=350-(4/3)x-----> equation 2
the answer part a) y=350-(4/3)x------> <span>
it was proved</span>
Part b)Find the possible lengths and widths of each pasture.
substitute equation 2 in equation 1
15000=x*y-----> 15000=x*[350-(4/3)x]
15000=350x-(4/3)x²----> multiply by 3----> 45000=1050x-4x²
4x²-1050x+45000=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=53.942 ft
x=208.558 ft
15000=x*y-----> y=15000/x
for x=53.94 ft
y=278.09 ft
for x=208.56 ft
y=71.92 ft
the possible lengths and widths of each pasture are
case 1
x=53.94 ft
y=278.09 ft
case 2
x=208.56 ft
y=71.92 ft