I need your help pls help me I make u big brain\

Andrew [12]

Part A: Group A is a cluster of points. Group B Is not even a group this point is an outlier. A possible reason Point B is involved is because there could be a student that although played a lot of video games, he studied too and got a good score.

Part B: The association is a negative linear association. Also as students play more video games the test scores tend to go down.

Hope This Helps!

4 0

3 years ago

URGENT !!!!!!!!!!!! Please answer correctly !!!!!!!!! Will<br> Mark Brianliest !!!!!!!!!!!!!!!!

mina [271]

Answer:

MLH is congruent to JKI

LNK is congruent to HNI

I think that's how you're supposed to answer it...

3 0

3 years ago

To find the height of a tower, a surveyor positions a transit the is 2 meters tall at a spot of 40 meters from the base of the t

Mrac [35]

The height of the tower roughly equals 41.421 meters.

5 0

4 years ago

What is the equation of the rational function g(x) and its corresponding slant asymptote?

bija089 [108]

The solution to the Questions are

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

Decision rule: If z > 2.05 or z<-2.05, reject H0

z=2.59

The two-tailed nature of the test is shown by the alternative hypothesis.
The result of the test yields the following P-value: 0.0096

<h3>What is the alternate hypothesis?</h3>

(a)

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

(b)

Here we have

$n_{1}=40,\\\\ \bar{x}_{1}=102,\sigma_{1}=5,n_{2}=50,\bar{x}_{2}=99,\sigma_{2}=6$

(b)

Here the test is two-tailed. So for $\alpha =0.04$ , the critical values of the z-test are -2.05 and 2.05.

Decision rule: If z > 2.05 or z<-2.05, reject H0

(c)

Test statistics will be

$z=\frac{(\bar{x}_{1}-\bar{x}_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} \\\\\\z=\frac{(102-99)-(0)}{\sqrt{\frac{5^{2}}{40}+\frac{6^{2}}{50}}}$

z=2.59

(d)

The two-tailed nature of the test is shown by the alternative hypothesis.

(e)

The result of the test yields the following P-value: 0.0096

Read more about P-value

brainly.com/question/14790912

#SPJ1

4 0

3 years ago

A rancher constructs two rectangular horse pastures that share a side, as shown. The pastures are enclosed by 1050 feet of fenci

noname [10]

The complete question in the attached figure

we know that
area each pasture=15000 ft²
area each pasture=x*y
so
15000=x*y-----> equation 1

perimeter two rectangular pastures=1050 ft
perimeter two rectangular pastures=2*[2x+y]+y----> 4x+2y+y---> 4x+3y
so
1050=4x+3y----> divide by 3----> 1050/3=(4/3)x+y
clear variable y
y=350-(4/3)x-----> equation 2

the answer part a)
y=350-(4/3)x------> <span>it was proved
</span>
Part b)Find the possible lengths and widths of each pasture.
substitute equation 2 in equation 1
15000=x*y-----> 15000=x*[350-(4/3)x]
15000=350x-(4/3)x²----> multiply by 3----> 45000=1050x-4x²
4x²-1050x+45000=0

using a graph tool----> to resolve the second order equation
see the attached figure

the solution is
x=53.942 ft
x=208.558 ft

15000=x*y-----> y=15000/x

for x=53.94 ft
y=278.09 ft

for x=208.56 ft
y=71.92 ft

the possible lengths and widths of each pasture are
case 1
x=53.94 ft
y=278.09 ft

case 2
x=208.56 ft
y=71.92 ft

7 0

4 years ago