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Archy [21]
3 years ago
10

What are the solutions?

Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

I and III

Step-by-step explanation:

All you have to do is plug the values in for x

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I can’t see the options lol show them
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(C) 143g increased by 19%​
Deffense [45]

Answer:

170.17g

Step-by-step explanation:

5 0
2 years ago
The two functions below are used to represent the height of a rocket above the ground after it is launched. Which rocket reaches
Korvikt [17]

Answer:

  Rocket B reaches a maximum height that is greater than the maximum height of Rocket A.

Step-by-step explanation:

A graph quickly shows the answer to this question.

__

In vertex form, the equation for Rocket A is ...

  y = -6(x² -16x +8²) +6(8²)

  y = -6(x -8)² +384 . . . . . . . . . maximum height is 384 feet

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The corresponding equation for Rocket B is ...

  y = -4(x² -20x +10²) +4(10²)

  y = -4(x -10)² +400 . . . . . . . . maximum height is 400 feet

Rocket B reaches a maximum height greater than that of Rocket A.

7 0
3 years ago
Read 2 more answers
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Find area of triangle whose base is 2 √3 and height is 3 √3
Lera25 [3.4K]
Area of a triangle = base times height
A = 2√3 times 3√3
A = 18
The answer is 18
Hope that helps
7 0
3 years ago
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