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LiRa [457]
3 years ago
9

Find the x-intercept of the graph of the function y=3/2x-6

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

Answer:

x-int. = 4, if the equation is written correctly

Step-by-step explanation:

To find x- intercept y should be =0,

y = 0

y=3/2x-6

0= 3/2x - 6

6 *2/3= 3/2 x* 2/3

4 = x

x- int = 4

You can see it also from the graph

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The sum of three consecutive even integers is −246. Find the three integers.
Karolina [17]

Answer:

-83, -82, and -81

Step-by-step explanation:

Step 1: Declare your variable

Let x represent the largest of the 3 consecutive integer

Integer 1: x

Integer 2: x + 1

Integer 3: x + 2

Step 2: Create an equation

(x) + (x + 1) + (x + 2) = -246

Step 3: Solve

x + x + 1 + x + 2 = -246

3x + 3 = -246

3x = -249

\frac{3x}{3}=\frac{-249}{3}

x = -83

FInd the other 2 numbers

Integer 1: -83

Integer 2: -82

Integer 3: -81

Step 4: Therefore Statement

Therefore the 3 consecutive numbers are -83, -82, and -81

3 0
3 years ago
Who is the Knight of the White Moon? A. the barber B. Samson Carrasco C. Sancho Panza D. the curate
uysha [10]
The most likely solution is A
8 0
3 years ago
Read 2 more answers
What are the numbers of pi
guapka [62]

Answer:

3.14159265358979323846264338 and so forth

Step-by-step explanation:

I hope this helps

4 0
3 years ago
Remember to simplify your answer (make improper fractions mixed numbers) 3/4÷1/5​
hoa [83]

Answer:

4/15

Step-by-step explanation:

5 0
3 years ago
The animal shelter had a special on adoption rates for their dogs and cats. Each dog adoption fee was $75 and each cat adoption
lidiya [134]

Answer:

3 dogs and 5 cats were adopted out on Christmas eve.

Step-by-step explanation:

Let the number of dogs adopted out on Christmas eve be x and the number of cats be y.

From the question,

On Christmas Eve, the animal adopted out 8 total animals

That is, x + y = 8 ...... (1)

and brought in $400 in total adoption fees.

Also from the question,

Each dog adoption fee was $75 and each cat adoption fee was $35.

∴ On Christmas Eve,

75x + 35y = 400 ...... (2)

Now, to determine how many dogs and how many cats were adopted out on Christmas Eve, we will solve the two equations simultaneously.

From equation (1)

x + y = 8

Make x the subject of the relation.

∴ x = 8 - y ...... (3)

Substitute the value of x into equation (2)

75(8 - y) + 35y = 400

600 - 75y + 35y = 400

600 -40y = 400

600 - 400 = 40y

200 = 40y

∴ 40y = 200

y = 200/40

y = 5

Substitute the value of y into equation (3)

x = 8 - y

x = 8 - 5

x = 3

∴ x = 3 and y = 5

Hence, 3 dogs and 5 cats were adopted out on Christmas eve.

4 0
3 years ago
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