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3 years ago

- Which expression is equivalent to 3x+10-x+12

Mathematics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

3x-x+= 2x

10+ 12= 22

Answer - 2x+22

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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

What is the length of EF ? A. 8 pi B. 4 pi C. 2 pi D. Pi

Pani-rosa [81]

I think the answer is B

5 0

3 years ago

The endpoints of on are located at O(1, 2) and N(3, 1). Using slope-intercept form, write the equation of line on.

Naddika [18.5K]

y = -1/2x +2 1/2
General equation;
y = mx + c

Calculating the slope;
Change in y/ (change in x) = gradient m

(2-1)/(1-3) = - 1/2

Replacing m gives;
y= -1/2x + c

Calculating the value of c
take point (1,2) above and replace y with 2 and x with 1
2=-1/2 *1 +c
c = 2 1/2
Equation then is
y = -1/2x +2 1/2

7 0

3 years ago

Ahhhh help everyone help me solve this ....

vovangra [49]

Answer:

$y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

Step-by-step explanation:

$\frac{3wx}{ \sqrt{2y} } = \frac{5}{2z} \\ \\ \sqrt{2y} \times 5 = 3wx \times 2z \\ \\ \sqrt{2y} \times 5 = 6wxz \\ \\ \sqrt{2y} = \frac{6wxz}{5} \\ \\ {( \sqrt{2y} })^{2} = {( \frac{6wxz}{5} })^{2} \\ \\ 2y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \div 2 \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \times \frac{1}{2} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{50} \\ \\ \\ y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

I hope I helped you^_^

4 0

3 years ago

Factorize: Challenge problem: x^2+19x+78 help :)

Trava [24]

Answer:

(x + 6)(x + 13)

Step-by-step explanation:

Given

x² + 19x + 78

Consider the factors of the constant term (+ 78) whuch sum to give the coefficient of the x- term (+ 19)

The factors are + 6 and + 13 , since

6 ×13 = + 78 and 6 + 13 = + 19 , then

x² + 19x + 78 = (x + 6)(x + 13) ← in factored form

3 0

3 years ago

Read 2 more answers