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Black_prince [1.1K]
3 years ago
6

How high up on a wall does a 50 ft ladder reach if the bottom of the ladder is placed 14 ft from the base of the building

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

48 ft

Step-by-step explanation:

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Volume of a cube is a side length cubed

So 7*7*7

Answer is 343 centimeters
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What is the answer to 66- = R2
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R=-33

Step-by-step explanation:

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Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
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Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
4 years ago
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If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v
pochemuha

Answer:

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = 5000(1 - \frac{1}{40}t )^2  , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = 2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )

V'(t) = 2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )

When we simplify the above, we get

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0
4 years ago
Help pls, math due tonight :(
Olenka [21]

9514 1404 393

Answer:

  • 40 ft
  • t = 1 second

Step-by-step explanation:

A graphing calculator answers these questions easily.

The ball achieves a maximum height of 40 ft, 1 second after it is thrown.

__

The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.

  h(t) = -16(t^2 -2t) +24

  h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square

  h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form

Compare this to the vertex form:

  f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'

We see the vertex of our height equation is ...

  (h, k) = (1, 40)

The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.

8 0
3 years ago
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