Should i write a song and post it?

Morgan has $60 to spend on clothes. He wants to buy a pair of jeans for $25 and spend the rest on t-shirts. Each t-shirt costs $

ZanzabumX [31]

Morgan has $60.

$60 - $25 = $35

$35/$5 = 7

The value of x CANNOT be greater than 7 but certainly equal to 7.

Answer: : x ≤ 7

7 0

3 years ago

Read 2 more answers

world population is increasing by 1.2% each year. In 2008, it was 6.68 billion. What will the population be in 2015?

SSSSS [86.1K]

Hello! For this question, we are compounding. The formula for compounding is P(1 + r)^t, where P = initial amount, r = rate, and t = time in years. In this problem, the rate is 1.2%. 1.2% is 0.012 in decimal form. Let's add 1 to that. 1 + 0.012 is 1.012. That part is done. Next, we raise it to the 7th power, because 2008 to 2015 is 7 years apart. 1.012^7 is 1.08708521101. This is a long decimal, but do not delete it from your calculator. Now, we multiply that number by 6.68 billion, which is 6,680,000,000 in standard form. When you do that, you get 7,261,729,209.52 or 7,261,729,210 when rounded to the nearest whole number. There. The world population will be 7,261,729,210 by 2015.

6 0

3 years ago

Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of

frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

3) $\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

4) $df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 21 37 58 116

Not Married 59 63 42 164

Total 80 100 100 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is $\alpha=0.05$

Part 2

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{80*116}{280}=33.143$

$E_{2} =\frac{100*116}{280}=41.429$

$E_{3} =\frac{100*116}{280}=41.429$

$E_{4} =\frac{80*164}{280}=46.857$

$E_{5} =\frac{100*164}{280}=58.571$

$E_{6} =\frac{100*164}{280}=58.571$

And the expected values are given by:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 33.143 41.429 41.429 116

Not Married 46.857 58.571 58.571 164

Total 80 100 100 280

And now we can calculate the statistic:

$\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0

4 years ago

A tourist group arrived at the boat dock for a boat ride in the morning. There were 252 people in the group. Another tourist gro

seraphim [82]

Okay, so to get the answer we have to divide.

252(morning group) divided by 36 = 7 trips

288(afternoon group) divided by 36= 8 trips

7 + 8 =
Answer: 15trips

8 0

4 years ago

Graph the inequality B is greater than -3

nikdorinn [45]

The graph would be a shaded line all inclusive after -3

4 0

3 years ago