Answer:
The possible values of x are 90°, 30° and 150°.
Step-by-step explanation:
Given that,
sin(2x) = cos(x) where 0° ≤ x < 180°
We know that, sin(2x) = 2 sinx cosx
2 sinx cosx = cosx
Subtract cosx on both sides
2 sinx cosx - cosx = 0
cosx (2sinx-1)=0
It means, cosx = 0 and (2sin x -1 ) = 0
cos x = cos0 and sinx = 1/2
x = 90° and x = 30°, 150°
Hence, the possible values of x are 90°, 30° and 150°.
Y = mx + b
slope(m) = -1
(2,-4)...x = 2 and y = -4
now we sub and find b, the y int
-4 = -1(2) + b
-4 = -2 + b
-4 + 2 = b
-2 = b
y = -x - 2
x + y = -2 <== standard form
Answer:
1+(3×u-1÷2u)=1+(5u÷2)=(2+5y)÷1
The answer should be 2.5, because you are cutting the value that they gave you in half
Answer:
I've never done that before I'm confused too man