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Marat540 [252]
3 years ago
15

Carla packed this box with 1-centimeter cubes. what is the volume of the box?

Mathematics
1 answer:
Yuki888 [10]3 years ago
7 0

Answer: 60 cm three squared

You can observe in the picture attached that the box is a rectangular prism.

The volume of a rectangular prism can be found with this formula:

Where "l" is the length, "w" is the width and "h" is the height.

You know that the lenght of each side of those cubes is 1 centimeter. Therefore, you can multiply the number of cubes on each side of the box by 1 centimeter in order to find the lenght, the width and the height of the box:

Now you can substitute the lenght, the width and the height of the box into the formula shown at the beginning of the explanation:

Finally, evaluating, you get that the volume of the box is:

223 units

Step-by-step explanation:

brainly.com/question/14536184

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Math simplify (7a+5b-2c) + (5a+7b) + (2a-7c) + (2a-5b+3c) algebra
Alekssandra [29.7K]

Answer:

-10a^2+25ab-15ac+12a+12b-2c

Step-by-step explanation:

(7a+5b-2c)+(5a+7b)+(2a-7c)+(2a-5b+3c)

Distribute:

=7a+5b-2c+5a+7b+(2a)(2a)+(2a)(-5)+(2a)(3c)+(-7a)(2a)+(-7a)(-5b)+(-7a)(3c)

=7a+5b-2c+5a+7b+4a^2-10ab+6ac-10a^2+35ab-21ac

Combine all like terms:

=(4a^2-14a^2)+(-10ab+35ab)+(6ac-21ac)+(7a+5a)+(5b+7b)+(-2c)

=-10a^2+25ab-15ac+12a+12b-2c

6 0
3 years ago
PLEASEEEEEEEEEE HELPPPPPPPPPPP
ankoles [38]

Answer:

I would just guess, but if i were to actually think about it, i would think C. I hope it helps, and blame it on me if you fail.

Step-by-step explanation:

8 0
3 years ago
Wich one' is the right answer need help
kykrilka [37]

Answer:

C

Step-by-step explanation:

because density equal all the rest

8 0
2 years ago
Can i get help with this math?
Airida [17]
Sorry but am just in grade 1
7 0
3 years ago
the first term of a arithmetic sequence is 2 and the 4th term is 11, how do I find the sum of the first 50 terms
Rama09 [41]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
a_4=11\\
n=4
\end{cases}
\\\\\\
a_4=2+(4-1)d\implies 11=2+(4-1)d\implies 11=2+3d
\\\\\\
9=3d\implies \cfrac{9}{3}=d\implies \boxed{3=d}\\\\
-------------------------------\\\\

\bf \textit{now, what's the 50th term anyway?}
\\\\\\
n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
n=50\\
d=3
\end{cases}
\\\\\\
a_{50}=2+(50-1)3\implies a_{50}=2+147\implies a_{50}=149\\\\
-------------------------------\\\\

\bf \textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\quad 
\begin{cases}
n=50\\
a_1=2\\
a_{50}=149
\end{cases}\implies S_{50}=\cfrac{50}{2}(2+149)
7 0
4 years ago
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