The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Slope: (y2-y1)/(x2-x1)
(3-3)/(2-10) = 0/-8 = 0
The slope is 0
STV=STU+UTV
But,
STV=90° and STU = 75°
Therefore,
90=75+UTV => UTV = 90-75
Therefore, expression A is the one that can be used to find UTV.
<span>Let's solve your equation step-by-step.<span><span><span>5x</span>+<span><span>12</span><span>(<span><span>4x</span>+8</span>)</span></span></span>=25</span>Step 1: Simplify both sides of the equation.<span><span><span>5x</span>+<span><span>12</span><span>(<span><span>4x</span>+8</span>)</span></span></span>=25</span></span><span>Simplify: (Show steps)</span><span><span><span><span>7x</span>+4</span>=25</span>Step 2: Subtract 4 from both sides.<span><span><span><span>7x</span>+4</span>−4</span>=<span>25−4</span></span><span><span>7x</span>=21</span>Step 3: Divide both sides by 7.<span><span><span>7x</span>7</span>=<span>217</span></span><span>x=3</span><u>Answer:</u><span>x=<span>3</span></span></span>
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
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