A classmate is having trouble factoring special case polynomials?

Help me plsssssssssssss

Zinaida [17]

Answer:

40mph

Step-by-step explanation:

(60mph+20mph)/2

40

7 0

3 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

8 0

3 years ago

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Pablo generates the function f (x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

kondor19780726 [428]

Answer:

f(x + 1) = Five-halves f(x) (A)

Question:

The complete question as found in brainly( ID:13525864) is stated below.

Pablo generates the function f(x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

Which is an equivalent representation?

f(x + 1) = Five-halvesf(x)

f(x) = Five-halvesf(x + 1)

f(x + 1) = Three-halvesf(x)

f(x) = Three-halvesf(x + 1)

Step-by-step explanation:

f(x) = (3/2)(5/2)^(x-1)

Where 3/2 = three-halves and 5/2 = (five-halves)

To determine an equivalent representation, let's assign values to x to see the outcome and compare it with the options.

f(x) = (3/2)(5/2)^(x-1)

For x = 1

f(x) = (3/2)(5/2)^(1-1) = (3/2)(5/2)^(0)

f(x) =(3/2)(1) = 3/2

For x = 2

f(x) = (3/2)(5/2)^(2-1) = (3/2)(5/2)^(1)

f(x) =(3/2)(5/2)

So from the above assigned values

f(x=1) = 3/2

f(x=2) = f(x + 1) = f(1 + 1)

f(x + 1) = (3/2)(5/2)

Since f(x) = 3/2

f(x+1) = (3/2)(5/2) = f(x) × 5/2 = 5/2f(x)

From the options, an equivalent representation: f(x + 1) = Five-halves f(x)

(A)

5 0

3 years ago

The first two terms in an arithmetic progression are 57 and 46. The last term is -207. Find the sum of all the terms in this pro

statuscvo [17]

Answer:

-1875

Step-by-step explanation:

An arithmetic sequence has a common difference as a sequence. Here the common differnece is -11.

So our sequence so far looks like,

(57,46,35,24....). We know the last term of the sequence is -207 and we need to find the nth term of that series so we use arithmetic sequence

$a _{1} + (n - 1)d$

where a1 is the inital value,

d is the common differnece and n is the nth term.

We need to find the nth term so

$57 + (n - 1)( - 11) = - 207$

$(n - 1)( - 11) = - 264$

$n - 1 = 24$

$n = 25$

So the 25th term of a arithmetic sequence is last term, now we can use the sum of arithmetic sequence

which is

$\frac{a _{1} + a _{n} }{2} n$

$\frac{57 + ( - 207)}{2} (25) =$

$\frac{ - 150}{2} (25)$

$- 75(25) = - 1875$

6 0

2 years ago

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Algebra 1 : plssss help need done :/ <3 tysm 20 POINTS

Illusion [34]

Answer:

b, b

Step-by-step explanation:

3 0

3 years ago

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